If a,b,c are in A.P., prove that the following is also in A.P.: b+c-a,c+a - b, a+b - c
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okk ? I think it will be right
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Step-by-step explanation:
For AP a,b,c :
Common difference (d) = b-a = c-b
For AP b+c-a, c+a-b, a+b-c :
Common difference (D) = (c+a-b) - (b+c-a) = (a+b-c) - (c+a-b)
Or D= 2(a-b) = 2(b-c)
D= -2(d) = -2(d)
As the common difference is same, therefore it's in AP
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