Question

If A,B,C are interior angles of triangle ABC, TAN A+B /2 =?

Answer 1

HEYA!!!

Sin[(B+C)/2]

Since A+B+C=180 for interior angles of triangle ABC.

then B+C=180-A.

NOW   Sin [(180-A)/2]

              =Sin[90-(A/2)]                    

 since

Sin(90-A)=CosA

               =Cos(A/2)

HOPE IT WORKS!!

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#BeBrainly

Answer 2

Answer:

Step-by-step explanation:

In a triangle, sum of interior angles=180⁰

Α+B+C=180⁰

Α+B. =180⁰-C

(A+B)/2=(90⁰-C/2)

Taking tangent

tan(A+B)/2=tan(90⁰-C/2)

tan(A+B)/2=Cot(C/2)

Thank you!!

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