If a, b, c are in A.P., then 3^ax + 5, 3^bx + 5 ,3^cx + 5 are in
(1) A.P.
(2) G.P, only when x > 0
(3) G.P, if x < 0
(4) G.P, V x ≠ 0
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Answer:
GP
Step-by-step explanation:
since a,b,c, are in AP
a+c = 2b
check for GP
(if a,b,c are in GP then b^2 = a×c)
now product of end terms =
3^(ax+5) × 3^(cx+5)
= 3^[(ax+5)+(cx+5)]
= 3^2[(a+c)x+5)]
=3^2[bx+5)]
= square of middle term
So it forms GP for all values of x
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