If a ,b, c are in A. P then k^a ,k^, b k^c are in G.P is he correct justify?
tejesh87:
sorry i done a mistake b =(ac)^1/2 when a,b,c are in gp
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we know that b=a+c/2 becauce a,b,c are in ap we know that b=(ab)^1/2 . we should prove k^a,k^b,k^c are in gp. proof : k^b = k^a+c/2 then k^b=(k^a(k^b))^1/2. hence k^a, k^b,k^c are in gp
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