if a,b,c are in A.P then proof that (a-c) whole square=4(b square-ac) will are in A.P plz solve this
Answers
Answered by
1
a,b,c are in A.P so b-a=c-b
2b=a+c
4b^2=(a+c)^2
(a+c)^2_4ac=(a-c)^2
4b^2=(a-c)^2+4ac
4b^2-4ac=(a-c)^2
2b=a+c
4b^2=(a+c)^2
(a+c)^2_4ac=(a-c)^2
4b^2=(a-c)^2+4ac
4b^2-4ac=(a-c)^2
Similar questions