if a,b,c are in AP then prove b=a+c÷2
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Answer:
First term is t1=a
Second term t2=a+d=b
third term is t3=a+2d=c
Now a+c=a+(a+2d)=2a+2d=2(a+d)=2b
⇒a+c=2b
b=(a+c) /2
hence proved.
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