if a,b,c are in AP then prove that a+b,c+a and b+c are also in ap
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well theoritically if u add same number s to each term of an ap they always be in a ap
ap are in equal intervals .
a ,b,c are in ap 2b =a+c.
then -c,-b,-a are in ap
if u add a+b+c to all the terms u get your answer
a+b,c+a,c+b are in ap
or else a lengthy process u have to take 2b = a +c
and substitute with k ... very long no time so use property of ap and solve okay
ap are in equal intervals .
a ,b,c are in ap 2b =a+c.
then -c,-b,-a are in ap
if u add a+b+c to all the terms u get your answer
a+b,c+a,c+b are in ap
or else a lengthy process u have to take 2b = a +c
and substitute with k ... very long no time so use property of ap and solve okay
instablam:
thanks bro
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