If a,b,c are in arithmetic progression, then the value of (a+2b-c)(2b+c-a)(c+a-b) = ?
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a, b, c are in AP so b=(a+c) /2..... 2b=a+c
given = (a+a+c-c) (a+c+c-a) (c+a-a-c) = 2a x 2c x 0 = 0
given = (a+a+c-c) (a+c+c-a) (c+a-a-c) = 2a x 2c x 0 = 0
AmanRajSinghania:
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