If a,b,c are in GP, then show that the following terms are in GP.
(1) 1/a,1/b,1/c
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Since they are in GP,
b^2 is ac
That means b/c is a/b.... (eq1)
1/b ÷ 1/a is a/b
1/c ÷ 1/b is b/c...
Since they are equal...
They are in GP
b^2 is ac
That means b/c is a/b.... (eq1)
1/b ÷ 1/a is a/b
1/c ÷ 1/b is b/c...
Since they are equal...
They are in GP
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