Question

if a b c are interior angle of triangle ABC then prove that cot A+B/2=tan C/2​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

⇒ (A + B + C) = 180°

⇒ (A + B) = 180˚ – C

⇒ (A + B)/2 = 90˚ – C/2

• Taking tan on both sides, we get

↠ tan (A + B)/2 = tan(90˚ - C/2)

= cot C/2

Hence proved.