Math, asked by rockstarruchir007, 8 months ago

If A,B,C are interior angles of ∆ABC i,e.A+B+C=180° then
1. sin{(B+C)/2}=?
2. tan{(B+C)/2)}-cot(A/2)



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Answers

Answered by boddusunetha
2

Answer:

1. cos(A/2)

2. 0

Step-by-step explanation:

thats the explanation

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