Question

If A, B, C are interior angles of triangleABC show that cosec²(B+C÷2)-tan²(A÷2)=1

Answer 1

Answer:

in triangle ABC  

           A + B + C=180(angle sum property)

           B+C=180-A

           (B+C)/2 = (180-A)/2 = 90-A/2

      applying cosec^2 on both sides we get  

           cosec^2(B+C/2) = cosec^2(90-A/2)

          cosec^2( B+C/2) = sec^2(A/2)

      cosec^2 (B+C /2) - tan^2 (A/2)= 1                          (sec^2 teta = 1 + tan^2 teta )

Step-by-step explanation:

Answer 2

Answer:

If A, B, C are interior angles of triangleABC show that cosec²(B+C÷2)-tan²(A÷2)=1 - did not match any news results.