Question

We know that H=I²Rt If I is halved, what will happen to the heat?

Answer 1

Explanation:

now, here you can see Heat is inversely proportional to resistance. so, if resistance of any electric circuit is halved , then the value of heat produced will be doubled. Heat produced =? so heat produced will be doubled.

Answer 2

Answer:

Heat is directly proportional to square of current. So, If current is halved then the heat becomes√1/2 times.

Explanation:

Resistance is a conductor's characteristic that governs transmission in a conductor. Conduction decreases as resistance increases. The following relationship can be used to determine a conductor's resistance

$R=\frac{\rho l}{A}$

Where $\rho$ is the specific resistance of the conductor.

l is the length of a conductor

A is the area of the cross section of a conductor.

Srep 1: Heating effect is produced in a conductor when current flows in a conductor for some interval of time. The basic cause of the heating effect is resistance; more is the resistance more is the heating effect. So it can be represented by the relation -

$H=I^2 R t$ (Equation 1)

According to ohm's Law, $V=I R$

$\Rightarrow I=\frac{V}{R}$

Put the value of I in quation 1 , we get

$H=\frac{V^2 t}{R}$

Step 2: Heating effect of current in a conductor can be given by the above relation. It shows that heating effect is directly proportional to applied voltage and time and inversely proportional to resistance of a conductor.

According to the question, Resistance of wire gets halved then heating effect also gets affected.

As we know that

$H=\frac{V^2 t}{R}$

Since here applied voltage is constant. So above equation can be written as :-

$\Rightarrow H \propto \frac{1}{R}$

Step 3: So according to this relation heating effect of current is inversely proportional to resistance.

When resistance gets halved so new resistance will be represented by $R^{\prime}$

$\Rightarrow R^{\prime}=\frac{R}{2}$

Let us assume $\mathrm{R}^{\prime}$ be the new resistance of the conductor.

Apply this logic to Equation 1.

Then new heating effect will calculate by -

$\begin{aligned}& \Rightarrow \frac{H^{\prime}}{H}=\frac{R}{R^{\prime}} \\& \Rightarrow \frac{H^{\prime}}{H}=2 \\& \therefore H^{\prime}=2 H\end{aligned}$

Heating effect of a conductor gets doubled when resistance of conductor gets halved.

Here, heat is directly proportional to square of current. So, If current is halved then the heat becomes√1/2 times.

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