if a,b,c are positively real number such that a+b-c/c=a-b+c/b=-a+b+c/a,find the value of (a+b)(b+c)(c+a)/abc
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11
and you can substitute the -1 in k you will get8
I hope it is useful to you
I hope it is useful to you
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esha55:
i dint understood and also u dint find out k
sry
u got -1
Yes,there is a solution if a=b=c.If a=b=c,then a+b-c/c=a-b+c/b=-a+b+c/a=1.
ok tq
a+b-c/c=1,a+b-c=c,a+b=2c.
tqq
thank
Take a and b as c.Then ,a+b=2c,c+c=2c,2c=2c.If we substitute any number except 1 in place of K we will get wrong answer.
Therefore,K=1 and answer is 8.
Answered by
7
a+b-c/c=a-b+c/b=-a+b+c/a=8.
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