if a b c are subsets of universal set u prove that (a union b)' = a' intersection b'
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Answer:
Given n(U)=692,n(B)=230,n(C)=370,n(B∩C)=20, n(A∩B
′
∩C
′
)=10
n(A
′
∩B
′
∩C
′
)=n((B
′
∩C
′
)∩A
′
)
n(A
′
∩B
′
∩C
′
)=n((B∪C)
′
∩A
′
)
=n((B∪C)
′
)−n((B∪C)
′
∩A)
=n(U)−n(B∪C)−n(A∩B
′
∩C
′
)
=n(U)−n(B)−n(C)+n(B∩C)−n(A∩B
′
∩C
′
)
=692−230−370+20−10=102
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