Question

If A, B, C are the angles of a triangle, show that,
(i) sin Bcos(C+ A) + cos B sin(C+ A) = 0​

Answer 1

Step-by-step explanation:

it is equal to one because the sign in between is plus

sinBcos(90-B)+cosBsin(90-B)

sin^2(B)+cos^2(B)

=1

as sin square theeta + cos square theeta is one ((((((((( trig identity))))))

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