Question

If a,b,c are three consecutive positive integers, then Log(1+ca)=

Answer 1

this is the step by step solution

Answer 2

Answer:

$2\log b$

Step-by-step explanation:

Given,

a,b,c are three consecutive positive integers,

i.e. b = a + 1 and c = a + 2,

Now,

$\log( 1 + ca )$

$= \log ( 1 + (a+2)a)$

$= \log ( 1 + a^2+ 2a)$              ( By distributive property ),

$= \log ( 1 + a )^2$                ( ∵ (x+y)² = x² + 2xy + y² )

$= 2\log ( 1 + a )$                  ( $\log x^y = y\log x$ )

$= 2\log b$