if a(b+c)=(b^2-c^2)/d and b>c the a is equivalent to
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Answer:
Step-by-step explanation:
Given a,b,c,d are in continued proportion
⟹
b
a
=
c
b
=
d
c
=k(say)
⟹c=dk,b=ck=k
2
d,a=bk=k
3
d
LHS=(a
2
−b
2
)(c
2
−d
2
)=(k
6
d
2
−k
4
d
2
)(k
2
d
2
−d
2
)=k
4
d
4
(k
2
−1)
2
=(k
4
d
2
−k
2
d
2
)
2
=((k
2
d)
2
−(kd)
2
)
2
=(b
2
−c
2
)
2
=RHS
Hence Proved
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