Question

If a,b,c belong to Q and a+b+c=0, then the roots of (b+c-a)x^2+(c+a-b)x+(a+b-c)=0 are

Answer 1

you first put x=1 in equation

(b+c-a)+(c+a-b)+(a+b-c)=0

=> a+b+c=0

now question also given a+b+c=0
and x=1 is one root of equation

let r is another root of equation

sum of roots=r+1=-(c+a-b)/(b+c-a)
r =-2c/(b+c-a)