Math, asked by Rohancv, 1 year ago

The nature of the roots of (2y+5)(3y-4)=(y-3)(y+2) is

Answers

Answered by satya76
0
Given that (2y+5)(3y-4)=(y-3)(y+2)
6y^2-8y+15y-20=y^2+2y-6-3y
5y^2+8y-14=0
w.k.t nature of the root =b^2-4ac
nature of the root =(8)^2-4(5)(-14)
64+280
344>0
therefore the roots are real, distant
nature of the roots =∆
∆>0
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