Question

if A B C D are angles of a qudrilateral prove that sin (A +D)=sin ( B + C ) =0​

Answer 1

Answer:

Step-by-step explanation:

• A + B + C + D = 360
• (A+B) = 360 - (C+D)
• sin (A+B) = sin {360 - (C+D)} = -sin(C+D)
• So, sin(A+B) + sin(C+D) = -sin(C+D) + sin(C+D) = 0

Hope it helps