Question

If a, b, c, d are distinct positive numbers in A.P., then:
(A) ad<bc
(B) a+c<b+d
(C)a+d=2(b + c)
(D)a+d=3(b + c)
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Answer 1

Let the number a,b,c,d be x,x+d,x+2d,x+3d respectively.

So applying bit (A) we get,

L.H.S - x(x+3d)

=x^2 + 3xd

R.H.S - (x+d)(x+2d)

=x^2+2xd+xd+2d^2

=x^2+3xd+2d^2

So, LHS<RHS

Whether it is a increasing AP or decreasing AP, bit(A) will always be correct as the common difference gets squared in the equation.

So bit (A) is correct answer.

Answer 2

Answer:

Something

Step-by-step explanation:

System.out.println you can also use the same way as you