Question

what is the smallest number that,when divided by 35,56 and 91 leave remainder of 7 in each case?​

Answer 1

Answer:

3647

Step-by-step explanation:

We have to find LCM

So LCM of 35,56 and 91 is=

2*2*2*5*7*13+7=3647

Hence the answer is 3647 and it leave remainder of 7 in each case