Math, asked by diya0907, 1 year ago

what is the smallest number that,when divided by 35,56 and 91 leave remainder of 7 in each case?

Answers

Answered by maheshsaritha381

9

Answer:

3647

Step-by-step explanation:

We have to find LCM

So LCM of 35,56 and 91 is=

2*2*2*5*7*13+7=3647

Hence the answer is 3647 and it leave remainder of 7 in each case

maheshsaritha381: Hope it helps you dear student

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