Math, asked by BurnerBoi, 9 months ago

If a, b, c, d are in continued proportion, prove that:

5a^2 + 12c^2/5b^2 + 12d^2 = √3a^4 - √7c^4 / √3b^4 - √7d^2

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Answered by pallu723
4

If a, b, c, d are in continued proportion, prove that:

5a^2 + 12c^2/5b^2 + 12d^2 = √3a^4 - √7c^4 / √3b^4 - √7d^2

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Answered by cutebrainlyteacher72
2

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