Question

if a,b,c,d are in gp show that
(b - c)2 + (c – a)2 + (d – b)2 = (a - d)2.
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Answer 1

Answer:

$2(b - c) + 2( c- a) + 2(d - b) = 2(a - d) \\ or \: 2b - 2c + 2c - 2a + 2d - 2b = 2a - 2 d \\ or \: - 2a + 2d = 2a - 2d$

$or \: (a - d)2 = (a - d)2 \: \\ hence \: proved$

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