Question

If a, b, c, d are in proportion, then prove that a²+5c²/b²+5d²=a/b

Answer 1

Answer:

a²+5c²/b²+5d²= (a/b)²

Step-by-step explanation:

a : b :: c : d

=> a/b = c/d = K ( let say)

=> a = bK  & c =  dK

Correction on Question :

a²+5c²/b²+5d²= (a/b)²

LHS = (a²+5c²)/(b²+5d²)

=> ( (bK)² + 5(dK)²)/ ( b²+5d²)

= ( b²K² + 5d²K²) / ( b²+5d²)

= (K²(( b²+5d²))/  ( b²+5d²)

= K²

= (a/b)²

= RHS

Answer 2

Answer:

$\huge\underline\mathfrak\green{Solution}$