if a, b, c, d be in GP, prove that ax^(3) + bx^(2) + cx + d is divisible by (ax^(2) + c)
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10th
Maths
Polynomials
Division Algorithm for Polynomials
If ax^3 + bx^2 + cx + d is ...
MATHS
If ax
3
+bx
2
+cx+d is divisible by x
2
+h
2
, prove that ad=bc.
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ANSWER
Let the cubic equation ax
3
+bx
2
+cx+d is divisible by x
2
+h
2
.
Then we can write ,
ax
3
+bx
2
+cx+d=(x
2
+h
2
)(px+q)
ax
3
+bx
2
+cx+d=px(x
2
+h
2
)+q(x
2
+h
2
)
ax
3
+bx
2
+cx+d=px
3
+qx
2
+ph
2
x+qh
2
Therefore ,
upon comparing the both eqution we get ,
p=a
q=b
ph
2
=c
qh
2
=d
Thus ,
ad=pqh
2
bc=pqh
2
Thus ad=bc
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