Question

verify the identity

$(a - b) ^{2} = a^{2} - 2ab + b^{2}$
where a=6m,b=5m​

Answer 1

Answer:

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ {(6m - 5m)}^{2} = {(6m)}^{2} -( 2 \times 6m \times 5m) + {(5m)}^{2} \\ {(1m)}^{2} = {36m}^{2} - {60m}^{2} + {25m}^{2} \\ {m}^{2} = {61m}^{2} - {60m}^{2} \\ {m}^{2} = {1m}^{2} \\ {m}^{2} = {m}^{2} \\ \\ \huge \pink{ hence \: verified}$

WE USE IDENTITY- II HERE TO VERIFY GIVEN QUESTION.

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Answer 2

Step-by-step explanation:

${(6m - 5m)}^{2} = {m}^{2}$

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