if a, b, c, d, e, and f, are in A.P then ,e - c is equal to
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Let x be the common difference of the A.P. a,b,c,d,e,f.
As e is the 5th term
∴e=a+(5−1)x(∵a
n
=a+(n−1)d), where a_n is the nth term
⇒e=a+4x ...(1)
and c=a+2x ...(2)
∴ Using equation (1) and (2), we get
e−c=a+4x−a−2x
⇒e−c=2x=2(d−c)
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Let x be the common difference of the A.P.
a, b, c, d, e, f.
As e is the 5th term .
e = a + (5-1)x (an = a + (n − 1)d),
where a_n is the nth term
⇒ e = a + 4x ...(1)
and c = a + 2x ...(2) ...
Using equation (1) and (2), we get
e-c = a + 4x - a - 2x
⇒ e c = 2x = 2(d - c)
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