Math, asked by Ritukundu, 7 months ago

If a:b=C:d=e:f=1:2,then (3a+5c+7e ) : ( 3b+5d+7f ) is:

please help.... please... please​

Answers

Answered by janakiram1220
3

Answer:

1:2

Step-by-step explanation:

from a:b = 1:2, b= 2a

from c:d = 1:2, d= 2c

from e:f = 1:2, f= 2e

(3a + 5c + 7e) : ( 3(2a) + 5(2c) + 7(2e) )

(3a + 5c + 7e) : 2 (3a + 5c + 7e)

1 : 2 Answer

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