Question

If a:b=c:d then find the value of a²+b²/c²+d²

Answer 1

simple as that. It is by the k method.

Answer 2

a:b=c:d  (Given)

= (a/b) = (c/d)

Squaring both sides

= (a/b)^2 = (c/d)^2

= a^2/b^2 = c^2/d^2

Therefore

= (a^2/b^2) + 1 = (c^2/d^2) + 1

Now we can apply componendo to the above equation

= (a^2 + b^2)/b^2 = (c^2 + d^2)/d^2

= (a^2 + b^2)/(c^2 + d^2) = b^2/d^2

Hence the value is b^2/d^2