Question

If a, b,c >0 then
a/2a+b+c= b/a+2+c =c/ a+b+2c =?

Answer 1

Answer:

False,

by hit and trial putting value of a = 1,  b = 2, c = 3

a/(2a+b+c)= 1/(2 + 2 + 3) = 1/7

b/(a+2b+c) = 2/(1 + 4 + 3) = 2/8 = 1/4

c/( a+b+2c) = 3/(1 + 2 + 6) = 1/3

values are not equal

Hence proved