if a + b + C is equal to 6 and AB+ BC + CA is equal to 11 find the value of a cube plus b cube plus c cube minus 3 ABC
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a^3+b^3+c^3-3abc=(a+b+c)^3-3(ab+bc+ca)(a+b+c)
=216-198=18 looks good with 1 2 3
=216-198=18 looks good with 1 2 3
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