Question

if a ×b × c means (a +b)/c for all numbers except zero then (a × b × c) × a × b is equal to:​

Answer 1

Given :

a ×b × c means (a +b)/c for all numbers except zero

To Find :

(a × b × c) × a × b is

Solution :

•According to given relation

a × b × c = (a +b)/c for all numbers other than zero

So ,

(a × b × c) × a × b = (a +b)/c × a × b

•Now it is again of the type a × b × c

so it will be

(a × b × c) × a × b = (a +b)/c × a × b

=[ (a+b)/c + a ]/b

= [ ( a + b + ac ) / c ]/b

= ( a + b + ac ) /bc

•Hence ,(a × b × c) × a × b is

( a + b + ac ) /bc

Answer 2

Given :

a ×b × c means (a +b)/c for all numbers except zero

To Find :

(a × b × c) × a × b is

Solution :

•According to given relation

a × b × c = (a +b)/c for all numbers other than zero

So ,

(a × b × c) × a × b = (a +b)/c × a × b

•Now it is again of the type a × b × c

so it will be

(a × b × c) × a × b = (a +b)/c × a × b

=[ (a+b)/c + a ]/b

= [ ( a + b + ac ) / c ]/b

= ( a + b + ac ) /bc

•Hence ,(a × b × c) × a × b is

( a + b + ac ) /bc