if a+b+c=r and cos A=cosB.cosC .show that tan A =tanB+tanC
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Given A+B+C=π⟹A=π−(B+C)
And also given cosA=cosBcosC
⟹cos(π−(B+C))=cosBcosC
⟹−cosBcosC+sinBsinC=cosBcosC
⟹sinBsinC=2cosBcosC
⟹tanBtanC=2
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