Question

if a+b=c show b2+ac=c2-ab

Answer 1

Answer:

Step-by-step explanation:

Here a+b=c then, b=c-a

Take b^2+ac, here b=c-a

So, b^2+ac=(c-a)^2+ac

=c^2-2ca+a^2+ac

=c^2-ac+a^2

=c^2-a(c-a)

=c^2-a×b ; b=c-a

=c^2-ab

Then b^2+ac=c^2-ab

Answer 2

Answer:

a+b=c given

So b=c-a

To prove =b2+ac=c2-ab

L. H. S

b2+ac

Put value of b=c-a

(c-a) 2 +ac

c2+a2 -ac

R. H. S

c2-ab

Put value of b=c-a

c2-a(c-a)

c2-ac+a2

L. H. S=R.H.S