Question

If A + B + C=π
then find
the Value
sin2A+sin2B+sin2C​

Answer 1

Answer:

Please mark me

Step-by-step explanation:

Click here to get an answer to your question ✍️ If A + B + C = π , then prove that sin2A + sin2B + sin2C = 4sin Asin Bsin C

Answer 2

Answer: 4sinAsinBsinC

Solution:-

A+B+C = TT(pi) = 180degree

& sin2A+sin2B = 2sin(A+B)cos(A-B)

So, sin2A + sin2B + sin2C = 2sin(A+B)cos(A-B)+2sinCcosC

=2sinCcos(A-B) + 2sinCcosC

=2sinC(cos (A-B) - cos(A+B))

=2sinC2sinAsinB

=4sinAsinBsinC