Question

If A, B, C to X, Y, Z are 26 natural numbers, then the value of (x-a) (x-b) (x-c) to (x-y) (x-z) is what

Answer 1

Answer:

0

Step-by-step explanation:

(x-a) (x-b) (x-c).....(x-y) (x-z)=0 as there will be (x-x) also there which is 0

Answer 2

Answer:

The value is zero.

Step-by-step explanation:

It is given that A, B, C to X, Y, Z are twenty six natural numbers.

We need to determine the value of $(x-a) (x-b) (x-c) --- (x-y) (x-z)$.

It is observed clearly that there is product in between.

As it contain all the alphabets, there will be a term $(x-x)$ which is equal to zero.

A zero multiplied in this sequence will give result zero.

Hence, the value is zero.

#SPJ2