Question

if a,b,care natural numbers then find values of a,b,and c so that a+b+c-abc=0​

Answer 1

Answer:

Correct option is

C

13

We know that

b=

2

a+c

since they are in A.P

Hence 2b=a+c

2(a+b+c)=42

2a+2c+2b=42

2a+2c+a+c=42

3(a+c)=42

a+c=14

Therefore b=7

Now a,b,cϵN, we get

a=1,c=13,

a=2,c=12

:

:

:

a=13,c=1

Hence we will have 13 ordered pairs of (a,b,c) as a=(1,2,...13)

c=(13,12,11...1) and b=7

Answer 2

a b c are 1 2 3 respectively

1 + 2 + 3 - ( 1 * 2 * 3) = 0

Pls Mark BRAINLIEST