Question

If a,b,cbe the dimensions of the cuboid,V be it's volume and S be it's surface area,then prove (1/a+1/b+1/c)=S/2V.

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Answer 1

Answer:

Step-by-step explanation:

Answer 2

V = abc and S = 2(ab + bc + ca)

⇒S/2 = ab + bc + ca

Hence $\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{ab+bc+ca}{abc} = \frac{\frac{S}{2}}{V} = \frac{S}{2V}$.