If a+b=mb and 1/b +1/d=m/c, prove that
a,b,c and d are in proportion
Please help me to do this sum this is and proportion Sums
Answers
Answered by
63
Hello,
1/b+1/d=m/c
multiplies the second equation by c;
c/b+c/d=m
mutiplies everything by b
c+cb/d=mb;
c+cb/d=a+c;
subtracts c from both sides
bc/d=a;
multiplies
bc=ad;
divides both sides by bd
c/d=a/b
bye :-)
1/b+1/d=m/c
multiplies the second equation by c;
c/b+c/d=m
mutiplies everything by b
c+cb/d=mb;
c+cb/d=a+c;
subtracts c from both sides
bc/d=a;
multiplies
bc=ad;
divides both sides by bd
c/d=a/b
bye :-)
Answered by
6
Answer:b+d/bd = m/c(cross multiply)
Cb+cd = mb×d
Cb+cd =(a+c)×d
Cb+cd=ad+cd(as cd is common)
Cb=ad
a/b=c/d
Thusa:b::c:d
Step-by-step explanation:pls mark me brainliesttttt.....
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