If |a^-b^| =root 2, then calculate the value of |a^+root3b^|.
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a^=1
b^=1
so applying vector addition
(1)^2 +(1)^2 +2*1*1coso = 2
solving this you will get coso=0
theta = 90 degree.
then applying formula (1)^2 +(root3)^2 + 2*root3*coso
then solve this to get answer
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