If a=b to the power 2x and b=c to the power 2y and c=a to the power 2z find the value of xyz
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Step-by-step explanation:
Given,
a = b^2x
b = c^2y
c = a^2z
We have three equations. Pick any of the three equations and start solving. All will give the same answer.
I choose second equation.
b = c^2y
From last equation,
b = (a^2z)^2y
From first equation,
b = ((b^2x)^2z)^2y
Now, we know, (a^m)ⁿ = a^(mn)
Therefore,
b = b^(8xyz)
b¹ = b^(8xyz)
Comparing both sides,
8xyz = 1
Therefore,
xyz = 1/8
Hope it helps!
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