Math, asked by amktliv5, 10 months ago

If a=b to the power 2x and b=c to the power 2y and c=a to the power 2z find the value of xyz

Answers

Answered by manas3379
4

Step-by-step explanation:

Given,

a = b^2x

b = c^2y

c = a^2z

We have three equations. Pick any of the three equations and start solving. All will give the same answer.

I choose second equation.

b = c^2y

From last equation,

b = (a^2z)^2y

From first equation,

b = ((b^2x)^2z)^2y

Now, we know, (a^m)ⁿ = a^(mn)

Therefore,

b = b^(8xyz)

b¹ = b^(8xyz)

Comparing both sides,

8xyz = 1

Therefore,

xyz = 1/8

Hope it helps!

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