Math, asked by tanime4gnKarth, 1 year ago

if (a/b)^x-1 = (b/a)^2x-8 then find the value of x

Answers

Answered by mysticd
65
(a/b)^x-1=(b/a)^2x-8
(a/b)^x-1=(a/b)8-2x

powers are equal
x-1=8-2x
x+2x=8+1
3x=9
x=9/3
x=3
Answered by vrishintailor
4

Answer:

I think answer is

x=3

Step-by-step explanation:

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