if (a/b)^x-1 = (b/a)^2x-8 then find the value of x
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Answered by
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(a/b)^x-1=(b/a)^2x-8
(a/b)^x-1=(a/b)8-2x
powers are equal
x-1=8-2x
x+2x=8+1
3x=9
x=9/3
x=3
(a/b)^x-1=(a/b)8-2x
powers are equal
x-1=8-2x
x+2x=8+1
3x=9
x=9/3
x=3
Answered by
4
Answer:
I think answer is
x=3
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