Question

If (a+b)x+(2a-b)y=21 and 2x+3y=7have infinitely many solutions then what ate the values of a and b

Answer 1

Here,
(a + b)x + (2a - b)y = 21
2x + 3y = 7
A/c to question ,
infinity many solutions possible ,
so,
(a + b)/2 = (2a - b)/3 = 21/7

(a + b)/2 = 21/7 = 3

(a + b) = 6 ------(1)

again,
(2a - b)/3 = 21/7 = 3

(2a - b) = 9 --------(2)

solve equations (1) and (2)

3a = 15
a = 5 and b = 1

hence, if a = 5 and b = 1 then , infinitely many solutions possible of given equations.

Answer 2

Answer:

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