if a ball is dropped from a tower the height covered why the ball in last second is equal to the total height of the tower find out the height of the tower
Answers
Answered by
1
Answer:
Explanation:
A ball is dropped from the roof of a tower height =h
Total distance covered it in the last seconds of its motion
Solution
The distance covered in first 3 second
s=
2
1
at
2
=
2
1
×10×3
2
=45
If the ball takes in second to fall to ground. The distance covered in nth second
s
n
=u+
2
g
(2n−1)
=0+
2
10
(2×n−1)
=10n−5
Therefore, 45=10n−5
10n=50
n=5
Thereforeh=
2
1
=
2
1
gt
2
=
2
1
×10×25
=125m
Answered by
2
Answer:
s = ut + ½at²
where,
t = 1
u = 0 and,
a = 9.8 m/s
therefore,
s = 0 + ½ × 9.8 × 1
= 4.9 m
Note : the above answer is derived by taking acceleration equal to 9.8 m/s. If the acceleration is taken 10 m/s, then the answer would be 5 meters.
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