Question

if a ball is thrown up with speed of 15m/s what distance is covered before falling back. (g=9.8m/s)²​

Answer 1

Answer:

4.59m

At highest point v=o

Step-by-step explanation:

2as =v^2+u^2

2(9.8)s =0+15 ^2

S=90/19.6

S=900/196

S=4.59m