If a ball is thrown vertically upward with velocity of 40 m/s then what will be the magnitude of its displacement after 6s take g=10
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Answer:
60 m
Explanation:
Use equation of motion
- S = ut + 0.5at²
Where,
- S = Displacement covered in time "t"
- u = Initial velocity of object
- a = Acceleration of object
Acceleration due to gravity is in opposite direction of initial velocity. So we will take it as -10 m/s²
S = (40 m/s × 6 s) + (0.5 × -10 m/s² × (6 s)²)
= 240 m - 180 m
= 60 m
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