Question

If a balll is throne vertically downwards from height of tower 100 meter . In how much time body will strike the ground . g= 10 m/s -2​

Answer 1

Answer:

if the ball simply dropped from the tower then initial velo=0

so ,time taken ,t=

$\sqrt{2 \times distance \div g}{?} }$

Answer 2

★$\large\color{red} \mathrm{Hey \: There!}$★

Initial velocity (u) = 0m/s

Acceleration (a) = 10m/s^2

Height of tower (h) = 100m

Time taken to hit the ground (t) = ?

.

From Equations of motion:

h = ut + 1/2× (at^2)

100 = 0(t) + 1/2 × 10t^2

100 = 5t^2

5t^2 = 100

t^2 = 20

t = √20

t = 2√5

t = 4.47 sec.

Thus, the ball takes 4.47seconds to hit the ground after it was released.