Question

if a bar equal to 3 ICAP + 2 J cap + 2 k cap and b bar equal to two ICAP - 2 J cap + 4 k cap then unit vector perpendicular to the plane containing a bar and Bbar is

Answer 1

Answer:

(1/√22) (3i - 2j + 3k)

Explanation:

a = 3i + 2j  + 2k

b = 2i - 2j + 4k

Perpendicular Vector =

Product of A & B would be perpendicular

i   j  k

3  2  2

2 -2  4

= i ( 2*4 -(-2)*2)  - j (3*4 -2*2) + k (2*4 -(-2)*2)

= 12i - 8j + 12k

Magnitude of vector = √12² + 8² + 12² = √352

Unit Vector = (1/√352) (12i - 8j + 12k)

= (1/4√22)4(3i - 2j + 3k)

= (1/√22) (3i - 2j + 3k)

Answer 2

Explanation:

Okay na

the answer